//此函数是用来求3元一次方程ax^3+bx^2+cx+d=0的解.#include#includeusing namespace std;int main(){double diedai(double a,double b,double c,double d,double x);double a,b,c,d;double x=10000.0;cout>a>>b>>c>>d;x=diedai(a,b,c,d,x);cout<<x<<endl; return 0;}double diedai(dou...
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