lim[(2^n)/n!]=1 as n-->infinite（无穷）的结果应是不成立的正确的应该是lim[(2^n)/n!]=0 as n-->infinite（无穷）对任意x>0取m=int[2*1/x]+1则[(2^m)/m!]=(2/1)*(2/2)*(2/3)*(2/4)*...(2/(m-1))*(2/m)则只要取m>4就有!]=(2/1)*(2/2)*(2/3)*(2/4)*...(2/(m-1))<1则[(2^m)/m!]=(2/1)*(2/2)*(2/3)*(2/4)*...(2/(m-1))*(2/m)<2/m=2/(int[2*1/x]+1)=x/(1+x)<x于是，对于任意大于0的x，存在...
