怎样化简？

显示全部楼层 · 2013-7-9 15:34:02

原式=x[(1-x)/(1-x)-2/(1-x)]÷(x+1)-x(x-1)(x+1)/(x-1)2
=x[(1-x-2)/(1-x)]÷(x+1)-x(x+1)/(x-1)
=-x(x+1)/(1-x)÷(x+1)-x(x+1)/(x-1)
=x/(x-1)-x(x+1)/(x-1)
=(x-x2-x)/(x-1)
=-x2/(x-1) 【中学生数理化】团队为您解答！祝您学习进步不明白可以追问！满意请点击下面的【选为满意回答】按钮，O(∩_∩)O谢谢?...

千问 · 2013-7-9 15:34:02

原式=x×(1-x-2)/(1-x)×1/(x+1)-x(x+1)(x-1)/(x-1)2=x(x+1)/(x-1)×1/(x+1)-x(x+1)/(x-1)=(x-x2-x)/(x-1)=-x2/(x-1);您好，很高兴为您解答，skyhunter002为您答疑解惑如果本题有什么不明白可以追问，如果满意...

千问 · 2013-7-9 15:34:02

原式=x*[(1-x-2)/(1-x)]÷(x+1)-[x*(x+1)*(x-1)/(x-1)^2]=x*[(x+1)/(x-1)]÷(x+1)-[x*(x+1)/(x-1)]=x/(x-1)-x*(x+1)/(x-1)=[x/(x-1)]*[1-(x+1)]=[x/(x-1)]*(-x)=-x^2/(x-1)...

千问 · 2013-7-9 15:34:02

解原式=x[(1-x)/(1-x)-2/(1-x)]×1/(x+1)-x(x-1)(x+1)/(x-1)2=x(-1-x)/(1-x)×1/(x+1)-x(x+1)/(x-1)=x(1+x)/(x-1)×1/(x+1)-x(x+1)/(x-1)=x/(x-1)-x(x+1)/(x-1)=(x-x2-x)/(x-1)...