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(2k-1)/(x-2)+x/(x+2)=1(2k-1)/(x-2)+x/(x+2)-1=0(2k-1)/(x-2)+(x-x-2)/(x+2)=0(2k-1)/(x-2)-2/(x+2)=0(2k-1)(x+2)-2(x-2)=0(2k-1)x+2(2k-1)-2x+4=0(2k-3)x+4k+2=0方程的増根只能是x=2,或x=-2当x=2为増根时，2(2k-3)+4k+2=0,4k-6+4k+2=0,8k=4,k=1/2;当x=-2为増根时，-2(2k-3)+4k+2=0,-4k+6+4k+2=0,8=0所以x=-2不可能为増根所以 k=1/2，经检验k=1/2时确实有増根x=2，... |
