一道几何数学题！！！急急急急！！！快点解答！拜托了！谢谢

显示全部楼层 · 2013-7-22 20:40:30

(1)∠BPC=∠ABC/2 , ∠PCB=∠ACB/2∠BPC=180-(∠BPC+∠PCB)=180-(∠ABC/2+∠ACB/2)=180-(180-∠A)/2=90+∠A/2(2)∠PBC=∠ABC/2 , ∠ACP=∠ACE/2 , ∠ACE=180-∠ACB∠BPC=180-∠PBC-∠BCP=180-∠ABC/2-(∠ACB+∠ACP)=180-∠ABC/2-[∠ACB+(180-∠ACB)/2]=180-∠ABC/2-(90+∠ACB/2)=90-(∠ABC+∠ACB)/2=90-(180-∠A)/2=∠A/2(3)∠PBC=∠MBC/2 , ∠MBC=180-∠ABC∠PCB=∠BCN/2 , ∠BCN=180-∠...

千问 · 2013-7-22 20:40:30

<p=180-<pac-,pca
<p=180-1/2(<b-<c)
<a=180-<b-<c<p-<a=180-1/2(<b-<c) -180-<b-<c
=1/2(<b-<c) 2.
<a+1/2<b=<p+1/2<ace
<a+1/2<b=<p+1/2(<a+<b)<a=1/2<a+...

千问 · 2013-7-22 20:40:30

（1）∠BPC=180-1/2(∠ABC+∠ACB)∠A=180-(∠ABC+∠ACB)∠BPC=90+1/2∠A（2）∠ACE=∠A+∠ABC∠PCE=∠BPC+∠PBC=1/2∠ACE∠ABC=2∠PBC∠BPC=1/2∠A（3）∠P=180-(∠PBC+∠PCB)=180-1/2(∠MBC+∠BCN)=180-1/2...

千问 · 2013-7-22 20:40:30

解：∵∠A+∠ABC+∠ACB＝180∴∠ABC+∠ACB＝180-∠A∵BP平分∠ABC∴∠PBC＝∠ABC/2∵CP平分∠ACB∴∠PCB＝∠ACB/2∵∠BPC+∠PBC+∠PCB＝180∴∠BPC＝180-（∠PBC+∠PCB）＝180-（∠ABC/2+∠ACB/2）＝180-（∠ABC+∠ACB）/2＝1...

千问 · 2013-7-22 20:40:30

解：﹙1﹚，∠p=90°+?∠A﹙2﹚,∠p=?∠A﹙3﹚,∠p=90°-?∠A...