input 0 and (x+1)F(0)=0+0+c=0 SO C=0F(x+1)=a*(x+1)2+b*(x+1)+c=F(x)+x+1=ax2+bx+c+x+1
a*(x2+2x+1) +bx+b=ax2+(b+1)x+1
ax2+2ax+a+bx+b=ax2+(b+1)x+1
ax2+(2a+b)x+a+b=ax2+(b+1)x+1 so 2a+b=b+1and a+b=1then a=0.5b=0.5do more kinds of questions~be interested in the math~~Good luck~!