1/1×2+1/2×3......1\2008×2009

显示全部楼层 · 2009-9-27 20:06:07

（1-1/2）+（1/2-1/3）+(1/3-1/4)……+（1/2008-1/2009）=1-1/2+1/2-1/3+1/3-1/4+……+1/2008-1/2009=1-1/2009=2008/2009

千问 · 2009-9-27 20:06:07

sum = 0for integer in range( 1, 2009 ): sum1 = 1 / integer * ( integer + 1 ) sum += sum1print "%d" % sumsum = 2

千问 · 2009-9-27 20:06:07

裂项

千问 · 2009-9-27 20:06:07

（1-1/2）+（1/2-1/3）+(1/3-1/4)……+（1/2008-1/2009）=1-1/2+1/2-1/3+1/3-1/4+……+1/2008-1/2009=1-1/2009=2008/2009希望采纳