提取公因式法(要过程和答案，详细点）

显示全部楼层 · 2007-8-18 21:10:37

1.(x-2y)^2(2y-x+1)2.2ab(a+b)(a+3b)3.(x-y)^2(1+x-y)4.(a-b)(x-y)(x-y+1)5.-5q(x+y)6.x(3x-2)(x-2)7.(x-y)(a-b+c)(5m+6n)8.因为x2+2x-3=0所以2x2+4x-6=0所以2x2+4x=6因为2ax2+4ax+12=0所以2ax2+4ax=-12则a=-2

千问 · 2007-8-18 21:10:37

1.(X-2y)^2-(X-2y)^3 =(X-2y)^2-3 =(X-2y)^-1 =1/(X-2y)2.6ab(a+b)^2-4a^2b(a+b) =(a+b)〖6ab(a+b)-4a^2b〗 =(a+b)〖6a^2b+6ab^2-4a^2b〗 =(a+b)〖2a^2b+6ab^2〗 =(a+b)〖2ab(ab+3b)〗 =2ab(a+b)(ab+3b)3.(x-y)^2-(y-x)^3 =(y-x)^2-(y-x)^3 =(y-x)^2-3 =(y-x)^-1 =1/(y-x)4.(a-b)(x-y)^2-（a-b)(y-x) =(a-b)(y-x)^2-（a-b)(y-x) =(a-b)(y-x)^2-1 =(a-b)/(y-x)5.(x+y)(2p-q)-2(y+x)(2q-p)=(x+y)〖(2p-q)-2(2q-p)〗 =(x+y)〖2p-q-4q+2p〗 =(x+y)(4p-5q)6.(x-1)^2（3x-2)+(2-3x) =(x-1)^2（3x-2)-(3x-2) =(3x-2)〖(x-1)^2-1〗 =(3x-2)〖(x-1)^2-1^2〗 =(3x-2)〖(x-1)+1〗〖(x-1)-1〗 =(3x-2)·x(x-2) =x(3x-2)(x-2)7.5m(x-y)(a-b+c)-6n(y-x)(a-b+c)=5m(x-y)(a-b+c)+6n(x+y)(a-b+c) =(5m+6n)(x+y)(a-b+c)8.x^2+2x-3=0(x-1)(x+3)=0x1=1,x2=-3 当x=-3时,18a-12a+12=0,a=-2 当x=1时,2a+4a+12=0,a=-2 ∴a1=a2=-2

千问 · 2007-8-18 21:10:37

1.(x-2y)^2(2y-x+1) 2.2ab(a+b)(a+3b) 3.(x-y)^2(1+x-y) 4.(a-b)(x-y)(x-y+1) 5.-5q(x+y) 6.x(3x-2)(x-2) 7.(x-y)(a-b+c)(5m+6n) 8.a=-2

千问 · 2007-8-18 21:10:37

1.(x-2y)^2-(x-2y)^3=(x-2y)^2(1-x+2y)8.x^2+2x=3,2ax^2+4ax+12=02a(x^2+2x)+12=02a*3+12=0a=-12/6=-2