C语言问题(编写几个程序)

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查看11 | 回复2 | 2007-12-5 12:45:57 | 显示全部楼层 |阅读模式
- -`````````1.#includeint main(void){int d,n,i;long sum;sum=0;scanf("%d%d",&d,&n);for(;n>0;n--){sum=sum*10;sum=n*d;}printf("%ld",sum);return 0;}2.#includeint main(void){int i,n[3];double sum;n[0]=2;n[1]=3;for(i=1;iint main(void){unsigned int a[10000],i,n,max,min;unsigned long sum;float avg;scanf("%d",&a[0]);sum=a[0];for(i=0;a!=0;++i){scanf("%d",&a)sum=sum+a;}max=a[0];min=a[0];for(n=1;nmax)max=a[n];for(n=1;nmin)min=a[n];avg=(float)sum/i;printf("\n%d%d%d%d%d%d\n",i,sum,avg,max,min);return 0;}
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千问 | 2007-12-5 12:45:57 | 显示全部楼层
1.#include#includevoid main(){int d,n,i,sum=0;l:printf("\nPlease input d(1-9):");scanf("%d",&d);if(d9){printf("d should be in 1-9");goto l;}printf("Please input n:");scanf("%d",&n);for(i=1;ivoid main(){float sum=0,i=2,j=1,t;int k,n;printf("Please input n:");scanf("%d",&n);for(k=1;kvoid main(){int a[1000],i,count,average,max,min,k;float sum=0;for(i=0;ia[k]?a[k]:min;sum+=a[k];}printf("The sum is %f.\nThe average is %f.\n",sum,sum/i);printf("The max is %d,the min is %d",max,min); }
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千问 | 2007-12-5 12:45:57 | 显示全部楼层
1.#include "stdio.h"#include "conio.h"main(){int d,n,i;long sum=3,t,s=3;scanf("%d%d",&d,&n);t=d;for(i=1;imax) max=a;if(aint fun(int,int);int square(int);int main(){ int d,n,i; long sum; scanf("%d%d",&d,&n); for(i=1;iint main(){ int i,n,k=2,j=1; float x=2.0/1,sum=0; scanf("%d",&n); for(i=1;iint main(){
int a,count=-1,max,min,sun=0;
float ave;
do{
count++;
scanf("%d",&a);
if(count=0)
{ max=a;
min=a;
}
sum+=a;
if(a>max)
max=a;
if(a void main() { int i,j,product,sum; long sum1=0,sum2=0;scanf("%d%d",&d,&n);for(i=1;i<=n;i++) {
product=1;
sum=0;
temp=1;
for(j=1;j<=i;j++)
{
product*=10
temp=product*d;
sum1+=temp;
}
sum2+=sum1;
}printf("计算结果为: %ld",&sum2); }
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