初二整式...超难的题目

显示全部楼层 · 2007-12-10 22:03:27

{1+[1/(2^1)]}*{1+[1/(2^2)]}*{1+[1/(2^4)]}*{1+[1/(2^8)]}+[1/(2^15)] =3/2*5/4*17/16*257/256+2^15=2

千问 · 2007-12-10 22:03:27

能用图片发上来吗？

千问 · 2007-12-10 22:03:27

{1+[1/(2^1)]}*{1+[1/(2^2)]}*{1+[1/(2^4)]}*{1+[1/(2^8)]}+[1/(2^15)] ={(1-1/2^1)(1+1/2^1)(1+1/2^2)(1+1/2^4)(1+1/2^8)}+1/2^15=2(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)}+1/2^15=2(1-1/2^4)(1+1/2^4)(1+1/2^8)}+1/2^15=2(1-1/2^8)(1+1/2^8)}+1/2^15=2(1-1/2^16)+1/2^15=2-1/2^15+1/2^15=2