下面用a代替θ由韦达定理sina+cosa=(√3+1)/2sinacosa=m/2(sina)^2+(cosa)^2=1所以(sina+cosa)^2-2sincosa=1(2+√3)/2-m=1m=√3/22x^2-(√3+1)x+√3/2=0(x-√3/2)(2x-1)=0x=√3/2,x=1/2若sina=√3/2,cosa=1/2,则a=π/3若sina=1/2,cosa=√3/2,则a=π/6若sina=√3/2,cosa=1/2,则tana=√3,cota=1/√3(sina)^2/(sina-cot)+cosa/(1-tan)=(5√3-1)/4若sina=...
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