二次函数

显示全部楼层 · 2011-3-12 22:31:06

1) y=x2-mx+（m2+1）/2 = = x2 -mx + m2/4- m2/4 + (m2+1)/2=(x - m/2)2+ (m2+2)/4 > 0 与轴无交点y=x2-mx-(m2+2)/2的图像经过A,B两点2) 代入A点坐标 0 = 1 +m -(m2+2)/2 m2 - 2m = 0m(m-2) = 0m=0或 m=2(a) m = 0, y = x2 -1 = (x+1)(x-1), B点坐标(1, 0)(b) m = 2, y = x2-2x...

千问 · 2011-3-12 22:31:06

分析：△1=m^2-4(m^+1)/2=-m^2-20 (1) =====>y=x^2-mx-(m^2+2)/2 A,B在 (2)0=1+M-(M^2+2)/2 =====>M=? ====>F(X) ====>B (3)a=1>0开口上 x0=-b/2a=? ====>x≤x0...