解：(1)f(x)=f′(1)e^(x-1)-f(0)x+(1/2)x^2令x=0，则有f(0)=f′(1)/e即：f′(1)=f(0)e将f′(1)=f(0)e带入f(x)=f′(1)e^(x-1)-f(0)x+(1/2)x^2得：f(x)=f(0)e^x-f(0)x+(1/2)x^2求导得：f'(x)=f(0)e^x-f(0)+x 令x=1，则f'(1)=f(0)e-f(0)+1=f(0)e所以：f(0)=1f'(1)=e带入f(x)=f′(1)e^(x-1)-f(0)x+(1/2)x^2得：f(x)=e^x- x + (1/2)x^2 对f(x)=e^x- x +...
