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x''+0.2x'-0.4x=0.2u(t), x(0)=x'(0)=0.1.你用Laplace Transform 做吧。L(x'')+0.2L(x')-0.4L(x)=0.2L(u(t))(p^2)*X(p)-p*x(0)-x'(0)+0.2(p*X(p)-x(0))-0.4*X(p)=0.2/p,(p^2+0.2*p-0.4)*X(p)=0.2/p,X(p)=0.2/(p^3+0.2*(p^2)-0.4p)然后，你查Laplace Transform 表即可。或者用MAtlab 求解,代码如下：F=0.2/(s^3+0.2*s^2-0.4*s)；x(t)=ilaplace(F,s,t)然后，x(t)的表... |
