比如 5 7 9 11 14 这五个数 我要判断后者减前者时候等于2,等于2的占到总数百分之几

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查看11 | 回复3 | 2012-11-14 08:36:22 | 显示全部楼层 |阅读模式
Private Sub Command1_Click()Dim S1 As String, ss As StringDim K As Integer, l As Integer, k1 As Single, k2 As Single, k33 As SingleDim sk As Variant'S1 = "5 7 9 11 14"S1 = InputBox("请输入:", "输入提示", "")Do While InStr(1, S1, "") > 0 S1 = Replace(S1, "", " ")Loop sk = Split(S1, " ")k3 = 0k4 = 0For...
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千问 | 2012-11-14 08:36:22 | 显示全部楼层
Function GetCount(ByVal t As String) As StringDim s() As StringDim n As Singles = Split(t, " ")If UBound(s) > 0 Then
For i = 1 To UBound(s)
If Val(s(i...
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千问 | 2012-11-14 08:36:22 | 显示全部楼层
本题目中,5,7,9,11,14后者减前者,总的有10种不同机会。后者减前者=3的有3种。所以后者减前者=3的占3/10=30%不好意思,那帮不上你的忙了。...
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