1000l+100z+10y+x=4000x+400y+40z+4l996l+60z=390y+3999x332l+20z=130y+1333x1333x≤130y+1333x=332l+20z≤332*9+20*9=3168x≤3168/13337l=8,9而130y,20z都能被5整除,1333除以5余3当l=9时,166*9除以5余4不成立所以l=810z-65y=52z-13y=113y=2z-1≤2*9-1=17所以y=0,1显然y=1z=7所以x=2,y=1,z=7,l=82178*4=8712
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