java中如何计算出两个日期之间相差多少天

显示全部楼层 · 2018-9-14 11:09:18

java可以使用计算日期的天数差，以下是详细代码：import java.text.ParseException;import java.text.SimpleDateFormat;import java.util.Calendar;import java.util.Date;public class test16 {
/**
* @param args
* @throws ParseException
*/
public static void main(String[] args) throws ParseException {
// TODO Auto-generated method stub
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date d1=sdf.parse("2012-09-08 10:10:10");
Date d2=sdf.parse("2012-09-15 00:00:00");
System.out.println(daysBetween(d1,d2));
System.out.println(daysBetween("2012-09-08 10:10:10","2012-09-15 00:00:00"));
}
/**
* 计算两个日期之间相差的天数
* @param smdate 较小的时间
* @param bdate较大的时间
* @return 相差天数
* @throws ParseException
*/
public static int daysBetween(Date smdate,Date bdate) throws ParseException
{
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");
smdate=sdf.parse(sdf.format(smdate));
bdate=sdf.parse(sdf.format(bdate));
Calendar cal = Calendar.getInstance();
cal.setTime(smdate);
long time1 = cal.getTimeInMillis();
cal.setTime(bdate);
long time2 = cal.getTimeInMillis();
long between_days=(time2-time1)/(1000*3600*24);
return Integer.parseInt(String.valueOf(between_days));
}
/** *字符串的日期格式的计算 */
public static int daysBetween(String smdate,String bdate) throws ParseException{
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");
Calendar cal = Calendar.getInstance();
cal.setTime(sdf.parse(smdate));
long time1 = cal.getTimeInMillis();
cal.setTime(sdf.parse(bdate));
long time2 = cal.getTimeInMillis();
long between_days=(time2-time1)/(1000*3600*24);
return Integer.parseInt(String.valueOf(between_days));
}
}

千问 · 2018-9-14 11:09:18

(big.getTime() - small.getTime()) / (1000 * 60 * 60 * 24);

千问 · 2018-9-14 11:09:18

public long differ(Date date1, Date date2){
return date2.getTime() / 86400000 - date1.getTime()/ 86400000; }参考资料：http://blog.csdn.net/solomonxu/archive/2007/04/27/1587237.aspx

已赞过已踩过 date2.getTime()) {//date1大System.out.println((date1.getTime() - date2.getTime())/86400000);} else {//date2大System.out.println((date2.getTime() - date1.getTime())/86400000);}}

千问 · 2018-9-14 11:09:18

this is a good question.mark it.