已知函数f(x)=sinx+根号3cosx的图像关于直线x=a对称，则最小正数a的值

显示全部楼层 · 2013-4-28 10:03:59

f(x)=2sin（x+π/3)就是找对称轴 x+π/3=kπ+π/2解得x=kπ+π/6最小正直 x=π/6即为所求...

千问 · 2013-4-28 10:03:59

f(x)=sinx+√3cosx
=2(1/2sinx+√3/2cosx)
=2(cosπ/3sinx+sinπ/3cosx)
=2sin(x+π/3)所以可得对称轴为：x=kπ+π/6即：最小正数a=π/6...

千问 · 2013-4-28 10:03:59

(x)=sinx+√3cosx=2(1/2×sinx+√3/2×cosx)=2[(cosπ/3)×sinx+(sinπ/3)×cosx]=2sin(x+π/3)所以对称轴为x=kπ+π/6∴最小正数a=π/6...

千问 · 2013-4-28 10:03:59

f(x)=sinx+√3cosx=√2sin（x+π/4)=2sin(x+π/6)x+π/6＝kπ+π/2x=kπ+π/3当K=0时有x=π/3a＝π/3...