要过程！1.计算①(x-1-x+1分之8)×x+3分之x+1；

显示全部楼层 · 2013-10-18 21:57:14

①(x-1-x+1分之8)×x+3分之x+1；=（x2-1-8）/(x+1)×(x+1)/(x+3)=x-3;②x+3y分之x-y÷x2+6xy+9y2分之x2-y2-x+y分之2y；=(x-y)/(x+3y)×(x+3y)2/(x+y)(x-y)-2y/(x+y)=(x+3y)/(x+y)-2y/(x+y)=1;③（x-x+1分之2x）÷x2-1分之x2-2x+1=(x2+x-2x)/(x+1)×(x+1)(x-1)/(x-1)2=x(x-1)/(x-1)=x;您好，很高兴为您解答，skyhunter002为您答疑解惑如果本题...

千问 · 2013-10-18 21:57:14

①(x-1-x+1分之8)×(x+3)分之(x+1)=[(x+1)分之（x2-1-8)]×[(x+3)分之(x+1)]=[(x+1)分之（x-3)(x+3)]×[(x+3)分之(x+1)]=x-3 ②(x+3y)分之(x-y)÷(x2+6xy+9y2)分之(x2-y2)-(x+y)分之2y...