1向量a=(2根号3sinx,cos^2x),b=(cosx,2),f(x)=a●b
=2√3sinxcosx+2cos2x
=√3sin2x+cos2x+1
=2(√3/2sin2x+1/2cos2x)+1
=2sin(2x+π/6)+1 由2kπ+π/2≤2x+π/6≤2kπ+3π/2,k∈Z得kπ+π/6≤x≤2kπ+2π/3,k∈Z∴函数f(x)的单调递减区间为[kπ+π/6,2kπ+2π/3],k∈Z 2 将函数y=f(x)图像向左平移π/12个单位得到y=2sin[2(x+π/12)+π/6]+1=2sin(2x+π/3)+1图像,将所得图...
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